(Sample)Multiple Feedback High-pass Filter Design Tool - Result -
Calculated the Transfer Function for the multiple feedback high-pass filter, displayed on graphs, showing Bode diagram, Nyquist diagram, Impulse response and Step response.
Multiple Feedback Filter
Vin(s)→ | →Vout(s) |
G(s)= |
-1s^{2} s^{2}+2941.17647059s+4368949.00563 |
R1 = 3.3kΩ
R2 = 15kΩ
C1 = 0.068uF
C2 = 0.068uF
C3 = 0.068uF
Cut-off frequency
fc = 332.666155674[Hz]
Gain at f=∞Hz
G_{pk} = -1[times] (0)[dB]
Quality factor
Q = 0.710669054519
Damping ratio
ζ = 0.703562363974
Pole(s)
p = -234.0513869 +236.40372125i[Hz]
|p|= 332.666155674[Hz]
p = -234.0513869-236.40372125i[Hz]
|p|= 332.666155674[Hz]
|p|= 332.666155674[Hz]
p = -234.0513869-236.40372125i[Hz]
|p|= 332.666155674[Hz]
Zero(s)
z = 0[Hz]
|z|= 0[Hz]
z = -0[Hz]
|z|= 0[Hz]
|z|= 0[Hz]
z = -0[Hz]
|z|= 0[Hz]
Phase margin
pm= NAN[deg] (f =0[Hz])
Oscillation frequency
f = 236.40372125[Hz]
Overshoot (in absolute value)
The 1st peak g_{pk} = 0.21 (t =0.0011[sec])
The 2nd peak g_{pk} = -0.0093 (t =0.0032[sec])
The 3rd peak g_{pk} = 0.00042 (t =0.0053[sec])
The 2nd peak g_{pk} = -0.0093 (t =0.0032[sec])
The 3rd peak g_{pk} = 0.00042 (t =0.0053[sec])
Final value of the step response (on the condition that the system converged when t goes to infinity)
g(∞) = 0