OKAWA Electric Design

(Sample) Transfer Function Analysis and Design Tool - Result -

Calculated the Transfer Function, displayed on graphs, showing Bode diagram, Nyquist diagram, Impulse response and Step response.

Transfer Function Analysis

(Sample) Transfer Function:
G(s)= s+10000
s3+30s2+500s+10000

Pole(s)

p = -2.1552679847381 +19.611717445798i
      |p|= 3.1400937168562[Hz]
p = -25.689464030524
      |p|= 4.0886051858393[Hz]
p = -2.1552679847381-19.611717445798i
      |p|= 3.1400937168562[Hz]

Zero(s)

z = -10000
      |z|= 1591.549430919[Hz]

Phase margin

pm= -21[deg] (f =4[Hz])

Oscillation frequency:

f = 3.1213017740203[Hz]

Overshoot (in absolute value)

The 1st peak  gpk = 1.55 (t =0.2[sec])
The 2nd peak  gpk = 0.61 (t =0.36[sec])
The 3rd peak  gpk = 1.28 (t =0.52[sec])

Final value of the step response (on the condition that the system converged when t goes to infinity)

g(∞) = 1

β=
α=

Frequency analysis

Bode diagram
    Phase  Group delay
Nyquist diagram
Pole, zero
Phase margin
Oscillation analysis

Upper and lower frequency limits:
  f1= - f2=[Hz] (frequency limits are optional)

Transient analysis

Step response
Impulse response
Overshoot
Final value of the step response

Simulation time:
  0〜[sec] (optional)



Transfer Function Design Tools (Tools Show∇)


The form of α and β values is rewritten by this tool to design the transfer function at given some paramaters.

Order poles on s-domain

Poles are ordered on s-domain of the transfer function inputted form of α and β. G(s) is rewritten that it solve the following equation.
  G(s) = {the transfer function of inputted old α and β}×H(s)

  • 1st order system
          p=
  • 2nd order system
      
        p1,p2=±j
        p1,p2=exp(±j )

Order zeros on s-domain

The system of H(s) is setted zeros z, z1 and z2 of a given the following form. The matrix of α and β as transfer function G(s) is rewritten to add zeros. The G(s) is solved the following equation.
  G(s) = {the transfer function of inputted old α and β}×H(s)
If α and β was blank, G(s) = H(s).

  • 1st order system
      H(s)= s - z    z=
  • 2nd order system
      H(s)=(s - z1 )(s - z2 )
        z1,z2= ± j
        z1,z2=exp(±j )

Design from ζ and ω0 on a 2nd order system

Poles are ordered on s-domain of the transfer function inputted form of α and β. G(s) is rewritten that it solve the following equation.
  G(s) = {the transfer function of inputted old α and β}×H(s)
If α and β was blank, G(s) = H(s).

2nd order system
  
•Natural angular frequency ω0=[rad/s]
•Damping ratio ζ=

Design the coefficient of s2, s1, s0

G(s) is rewritten that it solve the following equation.
  G(s) = {the transfer function of inputted old α and β}×H(s)
If α and β was blank, G(s) = H(s).

the transfer function
  H(s)=β1s22s3   

  β1=0  β1=1  β1=

  β2=0  β2=2ζω0 β2=
    •Use the above form to input of ω0, ζ

  β3=0  β302  β3=
    •Use the above form to input of ω0

Convert frequency

ω0(natural angular frequency) from the transfer function of inputted α and β is converted that ω0 is multiplied by a given ωk.

  ωk=    

Convert gain

G(s) transfer function of inputted α and β is multiplied by a given K.
    G(s)←KG(s)

  K=    

Frequency analysis

Gain characteristics at the Bode Diagram (provides up to 1 minute)

Phase characteristics at the Bode Diagram (provides up to 1 minute)

Bode Diagram text data (provides up to 1 minute)






Nyquist Diagram text data (provides up to 1 minute)


Transient analysis





Step Response text data (provides up to 1 minute)